12 practice questions

Class 9 Maths: Theoretical Probability — Practice Questions with Answers

Exam-style CBSE practice questions on Theoretical Probability (The Mathematics of Maybe: Introduction to Probability). Try each one first, then reveal the correct answer and a step-by-step explanation. Free, from EduLevel — the AI teacher for CBSE.

Q1easy1 mark

A fair die is rolled once. The probability of getting an even number is:

  1. 1/2
  2. 1/3
  3. 1/6
  4. 2/3
Show answer & explanation
Answer: 1/2

Explanation: A fair die has 6 equally likely outcomes: 1, 2, 3, 4, 5, 6. The even numbers are 2, 4 and 6, giving 3 favourable outcomes. P(even) = 3/6 = 1/2.

Q2easy1 mark

When two fair coins are tossed together, the total number of outcomes in the sample space is:

  1. 4
  2. 2
  3. 3
  4. 8
Show answer & explanation
Answer: 4

Explanation: Each coin can land in 2 ways, head or tail, so the total outcomes = 2 × 2 = 4. The sample space is HH, HT, TH, TT. Note that HT and TH are different outcomes, so the answer is 4, not 3.

Q3easy1 mark

A bag contains 3 red balls and 5 black balls. One ball is drawn at random. The probability that it is red is:

  1. 3/8
  2. 5/8
  3. 3/5
  4. 1/3
Show answer & explanation
Answer: 3/8

Explanation: Total balls = 3 + 5 = 8, and each ball is equally likely to be drawn. Favourable outcomes (red balls) = 3. P(red) = 3/8. Writing 3/5 compares red with black instead of red with the total.

Q4easy1 mark

The probability that it will rain in Mumbai tomorrow is 0.85. The probability that it will NOT rain tomorrow is:

  1. 0.15
  2. 0.85
  3. 0.5
  4. 1
Show answer & explanation
Answer: 0.15

Explanation: Raining and not raining are complementary events, so their probabilities add up to 1. P(no rain) = 1 − 0.85 = 0.15.

Q5medium1 mark

In a dice game, two fair dice are thrown together. The probability of getting a total of 7 is:

  1. 1/6
  2. 5/36
  3. 7/36
  4. 1/12
Show answer & explanation
Answer: 1/6

Explanation: When two dice are thrown, the total number of outcomes = 6 × 6 = 36. The pairs giving a sum of 7 are (1,6), (2,5), (3,4), (4,3), (5,2) and (6,1), which is 6 outcomes. P(sum 7) = 6/36 = 1/6.

Q6medium1 mark

One card is drawn from a well-shuffled deck of 52 cards. The probability of getting a red face card is:

  1. 3/26
  2. 3/13
  3. 1/26
  4. 6/13
Show answer & explanation
Answer: 3/26

Explanation: A deck has 12 face cards (jacks, queens and kings), of which 6 are red, coming from hearts and diamonds. P(red face card) = 6/52 = 3/26. Taking all 12 face cards gives 12/52 = 3/13, which ignores the colour condition.

Q7medium1 mark

A bag contains 4 red, 3 blue and 5 green balls. One ball is drawn at random. The probability that it is NOT green is:

  1. 7/12
  2. 5/12
  3. 1/3
  4. 7/5
Show answer & explanation
Answer: 7/12

Explanation: Total balls = 4 + 3 + 5 = 12. Balls that are not green = 4 red + 3 blue = 7. P(not green) = 7/12. This is the same as 1 − P(green) = 1 − 5/12 = 7/12.

Q8medium1 mark

Three fair coins are tossed together. The probability of getting exactly two heads is:

  1. 3/8
  2. 1/8
  3. 1/2
  4. 2/3
Show answer & explanation
Answer: 3/8

Explanation: Three coins give 2 × 2 × 2 = 8 equally likely outcomes. Exactly two heads occurs in HHT, HTH and THH, which is 3 outcomes. P(exactly two heads) = 3/8.

Q9medium1 mark

At a school fete, tickets numbered 1 to 20 are mixed thoroughly and one ticket is drawn at random. The probability that the ticket bears a number which is a multiple of 3 or a multiple of 7 is:

  1. 2/5
  2. 3/10
  3. 7/20
  4. 1/2
Show answer & explanation
Answer: 2/5

Explanation: Multiples of 3 from 1 to 20 are 3, 6, 9, 12, 15, 18, which is 6 numbers, and multiples of 7 are 7 and 14, which is 2 numbers. No number up to 20 is a multiple of both 3 and 7, since 21 is greater than 20, so favourable outcomes = 6 + 2 = 8. P = 8/20 = 2/5.

Q10hard1 mark

Two fair dice are thrown together. The probability that the product of the two numbers on top is 12 is:

  1. 1/9
  2. 1/12
  3. 1/6
  4. 5/36
Show answer & explanation
Answer: 1/9

Explanation: Total outcomes = 6 × 6 = 36. The product is 12 for the pairs (2,6), (6,2), (3,4) and (4,3), which is 4 outcomes. P(product 12) = 4/36 = 1/9.

Q11hard1 mark

A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball at random is double the probability of drawing a red ball, the number of blue balls in the bag is:

  1. 10
  2. 5
  3. 15
  4. 20
Show answer & explanation
Answer: 10

Explanation: Let the number of blue balls be x, so the total is 5 + x. P(blue) = x/(5 + x) and P(red) = 5/(5 + x). Since P(blue) = 2 × P(red), we get x/(5 + x) = 10/(5 + x), so x = 10. Check: P(blue) = 10/15 = 2/3, which is exactly double P(red) = 5/15 = 1/3.

Q12hard1 mark

One card is drawn from a well-shuffled deck of 52 cards. The probability that the card is neither a red card nor a queen is:

  1. 6/13
  2. 7/13
  3. 1/2
  4. 11/26
Show answer & explanation
Answer: 6/13

Explanation: There are 26 red cards and 4 queens, but the 2 red queens get counted twice, so cards that are red or a queen = 26 + 4 − 2 = 28. Cards that are neither = 52 − 28 = 24. P = 24/52 = 6/13.

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